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Code doesn't work Created Jul 19, 2010

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Views: 1583     Replies: 2     Last reply Aug 7, 2010  
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InetBUG

Posts: 2

Registered:
Jul 19, 2010

Code doesn't work

Posted: Jul 19, 2010

In Opera and WebKit (Safari, Chrome) this code doesn't work - handle enabled, but when I slide him - content don't change. In Firefox all good. Thanks.

P.S. In IE this code work too.


var range = $('.range');
var selectorVar = $('.i .description, .i .service-hide');
range.rangeinput({progress: true});
var api = range.data('rangeinput');
api.setValue(0);
api.onSlide( function () {
	var superVar = api.getValue();
	if (superVar==0) { $('.i .service-hide').hide(); $('.i .description').show(); }
	if (superVar==1) { selectorVar.hide(); $('.i-1').show(); }
	if (superVar==2) { selectorVar.hide(); $('.i-2').show(); }
	if (superVar==3) { selectorVar.hide(); $('.i-3').show(); }
});

doro

Posts: 3

Registered:
Oct 22, 2009

» Code doesn"t work

Posted: Jul 30, 2010

Reply to: Code doesn't work, from InetBUG
i have the same problem with slider api. it works fine in ff and ie7...

InetBUG

Posts: 2

Registered:
Jul 19, 2010

» » Code doesn

Posted: Aug 7, 2010

Reply to: » Code doesn"t work, from doro
I find the answer. onSlide must be here:
var selectorVar = $('.i .description, .i .service-hide');
$('.rangeid').rangeinput({
	progress: true,
	onSlide: function (event, value) {
		if (value==0) { $('.i .service-hide').hide(); $('.i .description').show(); }
		if (value==1) { selectorVar.hide(); $('.i-1').show(); }
		if (value==2) { selectorVar.hide(); $('.i-2').show(); }
		if (value==3) { selectorVar.hide(); $('.i-3').show(); }
	}

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